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Simtel MSDOS 1992 September
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Simtel20_Sept92.cdr
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fortran
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linpklib.arc
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SPODI.FOR
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1984-01-06
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SUBROUTINE SPODI(A,LDA,N,DET,JOB)
INTEGER LDA,N,JOB
REAL A(LDA,1)
REAL DET(2)
C
C SPODI COMPUTES THE DETERMINANT AND INVERSE OF A CERTAIN
C REAL SYMMETRIC POSITIVE DEFINITE MATRIX (SEE BELOW)
C USING THE FACTORS COMPUTED BY SPOCO, SPOFA OR SQRDC.
C
C ON ENTRY
C
C A REAL(LDA, N)
C THE OUTPUT A FROM SPOCO OR SPOFA
C OR THE OUTPUT X FROM SQRDC.
C
C LDA INTEGER
C THE LEADING DIMENSION OF THE ARRAY A .
C
C N INTEGER
C THE ORDER OF THE MATRIX A .
C
C JOB INTEGER
C = 11 BOTH DETERMINANT AND INVERSE.
C = 01 INVERSE ONLY.
C = 10 DETERMINANT ONLY.
C
C ON RETURN
C
C A IF SPOCO OR SPOFA WAS USED TO FACTOR A THEN
C SPODI PRODUCES THE UPPER HALF OF INVERSE(A) .
C IF SQRDC WAS USED TO DECOMPOSE X THEN
C SPODI PRODUCES THE UPPER HALF OF INVERSE(TRANS(X)*X)
C WHERE TRANS(X) IS THE TRANSPOSE.
C ELEMENTS OF A BELOW THE DIAGONAL ARE UNCHANGED.
C IF THE UNITS DIGIT OF JOB IS ZERO, A IS UNCHANGED.
C
C DET REAL(2)
C DETERMINANT OF A OR OF TRANS(X)*X IF REQUESTED.
C OTHERWISE NOT REFERENCED.
C DETERMINANT = DET(1) * 10.0**DET(2)
C WITH 1.0 .LE. DET(1) .LT. 10.0
C OR DET(1) .EQ. 0.0 .
C
C ERROR CONDITION
C
C A DIVISION BY ZERO WILL OCCUR IF THE INPUT FACTOR CONTAINS
C A ZERO ON THE DIAGONAL AND THE INVERSE IS REQUESTED.
C IT WILL NOT OCCUR IF THE SUBROUTINES ARE CALLED CORRECTLY
C AND IF SPOCO OR SPOFA HAS SET INFO .EQ. 0 .
C
C LINPACK. THIS VERSION DATED 08/14/78 .
C CLEVE MOLER, UNIVERSITY OF NEW MEXICO, ARGONNE NATIONAL LAB.
C
C SUBROUTINES AND FUNCTIONS
C
C BLAS SAXPY,SSCAL
C FORTRAN MOD
C
C INTERNAL VARIABLES
C
REAL T
REAL S
INTEGER I,J,JM1,K,KP1
C
C COMPUTE DETERMINANT
C
IF (JOB/10 .EQ. 0) GO TO 70
DET(1) = 1.0E0
DET(2) = 0.0E0
S = 10.0E0
DO 50 I = 1, N
DET(1) = A(I,I)**2*DET(1)
C ...EXIT
IF (DET(1) .EQ. 0.0E0) GO TO 60
10 IF (DET(1) .GE. 1.0E0) GO TO 20
DET(1) = S*DET(1)
DET(2) = DET(2) - 1.0E0
GO TO 10
20 CONTINUE
30 IF (DET(1) .LT. S) GO TO 40
DET(1) = DET(1)/S
DET(2) = DET(2) + 1.0E0
GO TO 30
40 CONTINUE
50 CONTINUE
60 CONTINUE
70 CONTINUE
C
C COMPUTE INVERSE(R)
C
IF (MOD(JOB,10) .EQ. 0) GO TO 140
DO 100 K = 1, N
A(K,K) = 1.0E0/A(K,K)
T = -A(K,K)
CALL SSCAL(K-1,T,A(1,K),1)
KP1 = K + 1
IF (N .LT. KP1) GO TO 90
DO 80 J = KP1, N
T = A(K,J)
A(K,J) = 0.0E0
CALL SAXPY(K,T,A(1,K),1,A(1,J),1)
80 CONTINUE
90 CONTINUE
100 CONTINUE
C
C FORM INVERSE(R) * TRANS(INVERSE(R))
C
DO 130 J = 1, N
JM1 = J - 1
IF (JM1 .LT. 1) GO TO 120
DO 110 K = 1, JM1
T = A(K,J)
CALL SAXPY(K,T,A(1,J),1,A(1,K),1)
110 CONTINUE
120 CONTINUE
T = A(J,J)
CALL SSCAL(J,T,A(1,J),1)
130 CONTINUE
140 CONTINUE
RETURN
END