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Simtel MSDOS 1992 September
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Simtel20_Sept92.cdr
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msdos
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fortran
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linpklib.arc
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SSISL.FOR
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1984-01-07
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SUBROUTINE SSISL(A,LDA,N,KPVT,B)
INTEGER LDA,N,KPVT(1)
REAL A(LDA,1),B(1)
C
C SSISL SOLVES THE REAL SYMMETRIC SYSTEM
C A * X = B
C USING THE FACTORS COMPUTED BY SSIFA.
C
C ON ENTRY
C
C A REAL(LDA,N)
C THE OUTPUT FROM SSIFA.
C
C LDA INTEGER
C THE LEADING DIMENSION OF THE ARRAY A .
C
C N INTEGER
C THE ORDER OF THE MATRIX A .
C
C KPVT INTEGER(N)
C THE PIVOT VECTOR FROM SSIFA.
C
C B REAL(N)
C THE RIGHT HAND SIDE VECTOR.
C
C ON RETURN
C
C B THE SOLUTION VECTOR X .
C
C ERROR CONDITION
C
C A DIVISION BY ZERO MAY OCCUR IF SSICO HAS SET RCOND .EQ. 0.0
C OR SSIFA HAS SET INFO .NE. 0 .
C
C TO COMPUTE INVERSE(A) * C WHERE C IS A MATRIX
C WITH P COLUMNS
C CALL SSIFA(A,LDA,N,KPVT,INFO)
C IF (INFO .NE. 0) GO TO ...
C DO 10 J = 1, P
C CALL SSISL(A,LDA,N,KPVT,C(1,J))
C 10 CONTINUE
C
C LINPACK. THIS VERSION DATED 08/14/78 .
C JAMES BUNCH, UNIV. CALIF. SAN DIEGO, ARGONNE NAT. LAB.
C
C SUBROUTINES AND FUNCTIONS
C
C BLAS SAXPY,SDOT
C FORTRAN IABS
C
C INTERNAL VARIABLES.
C
REAL AK,AKM1,BK,BKM1,SDOT,DENOM,TEMP
INTEGER K,KP
C
C LOOP BACKWARD APPLYING THE TRANSFORMATIONS AND
C D INVERSE TO B.
C
K = N
10 IF (K .EQ. 0) GO TO 80
IF (KPVT(K) .LT. 0) GO TO 40
C
C 1 X 1 PIVOT BLOCK.
C
IF (K .EQ. 1) GO TO 30
KP = KPVT(K)
IF (KP .EQ. K) GO TO 20
C
C INTERCHANGE.
C
TEMP = B(K)
B(K) = B(KP)
B(KP) = TEMP
20 CONTINUE
C
C APPLY THE TRANSFORMATION.
C
CALL SAXPY(K-1,B(K),A(1,K),1,B(1),1)
30 CONTINUE
C
C APPLY D INVERSE.
C
B(K) = B(K)/A(K,K)
K = K - 1
GO TO 70
40 CONTINUE
C
C 2 X 2 PIVOT BLOCK.
C
IF (K .EQ. 2) GO TO 60
KP = IABS(KPVT(K))
IF (KP .EQ. K - 1) GO TO 50
C
C INTERCHANGE.
C
TEMP = B(K-1)
B(K-1) = B(KP)
B(KP) = TEMP
50 CONTINUE
C
C APPLY THE TRANSFORMATION.
C
CALL SAXPY(K-2,B(K),A(1,K),1,B(1),1)
CALL SAXPY(K-2,B(K-1),A(1,K-1),1,B(1),1)
60 CONTINUE
C
C APPLY D INVERSE.
C
AK = A(K,K)/A(K-1,K)
AKM1 = A(K-1,K-1)/A(K-1,K)
BK = B(K)/A(K-1,K)
BKM1 = B(K-1)/A(K-1,K)
DENOM = AK*AKM1 - 1.0E0
B(K) = (AKM1*BK - BKM1)/DENOM
B(K-1) = (AK*BKM1 - BK)/DENOM
K = K - 2
70 CONTINUE
GO TO 10
80 CONTINUE
C
C LOOP FORWARD APPLYING THE TRANSFORMATIONS.
C
K = 1
90 IF (K .GT. N) GO TO 160
IF (KPVT(K) .LT. 0) GO TO 120
C
C 1 X 1 PIVOT BLOCK.
C
IF (K .EQ. 1) GO TO 110
C
C APPLY THE TRANSFORMATION.
C
B(K) = B(K) + SDOT(K-1,A(1,K),1,B(1),1)
KP = KPVT(K)
IF (KP .EQ. K) GO TO 100
C
C INTERCHANGE.
C
TEMP = B(K)
B(K) = B(KP)
B(KP) = TEMP
100 CONTINUE
110 CONTINUE
K = K + 1
GO TO 150
120 CONTINUE
C
C 2 X 2 PIVOT BLOCK.
C
IF (K .EQ. 1) GO TO 140
C
C APPLY THE TRANSFORMATION.
C
B(K) = B(K) + SDOT(K-1,A(1,K),1,B(1),1)
B(K+1) = B(K+1) + SDOT(K-1,A(1,K+1),1,B(1),1)
KP = IABS(KPVT(K))
IF (KP .EQ. K) GO TO 130
C
C INTERCHANGE.
C
TEMP = B(K)
B(K) = B(KP)
B(KP) = TEMP
130 CONTINUE
140 CONTINUE
K = K + 2
150 CONTINUE
GO TO 90
160 CONTINUE
RETURN
END