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The Princeton Review - Algebra Smart
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00005_Text_5.txt
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1996-10-02
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No way. You got part of the wayÑ subtracting the 5 from both sidesÑ and then you stopped. You want x by itself, not 3x. How do you get it? Well, if to get rid of an added 5 you subtract 5, then to get rid of a multiplied 3 you must divide by 3.