Yup. Just multiply the second equation by 3 so it becomes 9y -3x = 0, revamp it so it becomes 9y = 3x, and subtract one equation from another. From there it’s a snap (sort of) to solve for y, and you can substitute the y back in to find x. Of course, you could also have multiplied the equations by something else to subtract the y’s. Either way, you’ve done an excellent job in finding this answer.
