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FLPT.BAS
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BASIC Source File
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1987-09-12
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2KB
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74 lines
'
' FLPT.BAS
'
' Displays how a given real value is stored in memory.
'
'
DEFINT A-Z
DECLARE FUNCTION MHex$ (X AS INTEGER)
DIM Bytes(3)
CLS
PRINT "Internal format of IEEE number (all values in hexadecimal)"
PRINT
DO
' Get the value and calculate the address of the variable.
INPUT "Enter a real number (or END to quit): ", A$
IF UCASE$(A$) = "END" THEN EXIT DO
RealValue! = VAL(A$)
' Convert the real value to a long without changing any of
' the bits.
AsLong& = CVL(MKS$(RealValue!))
' Make a string of hex digits, and add leading zeroes.
Strout$ = HEX$(AsLong&)
Strout$ = STRING$(8 - LEN(Strout$), "0") + Strout$
' Save the sign bit, and then eliminate it so it doesn't
' affect breaking out the bytes
SignBit& = AsLong& AND &H80000000
AsLong& = AsLong& AND &H7FFFFFFF
' Split the real value into four separate bytes
' --the AND removes unwanted bits; dividing by 256 shifts
' the value right 8 bit positions.
FOR I = 0 TO 3
Bytes(I) = AsLong& AND &HFF&
AsLong& = AsLong& \ 256&
NEXT I
' Display how the value appears in memory.
PRINT
PRINT "Bytes in Memory"
PRINT " High Low"
FOR I = 1 TO 7 STEP 2
PRINT " "; MID$(Strout$, I, 2);
NEXT I
PRINT : PRINT
' Set the value displayed for the sign bit.
Sign = ABS(SignBit& <> 0)
' The exponent is the right seven bits of byte 3 and the
' leftmost bit of byte 2. Multiplying by 2 shifts left and
' makes room for the additional bit from byte 2.
Exponent = Bytes(3) * 2 + Bytes(2) \ 128
' The first part of the mantissa is the right seven bits
' of byte 2. The OR operation makes sure the implied bit
' is displayed by setting the leftmost bit.
Mant1 = (Bytes(2) OR &H80)
PRINT " Bit 31 Bits 30-23 Implied Bit & Bits 22-0"
PRINT "Sign Bit Exponent Bits Mantissa Bits"
PRINT TAB(4); Sign; TAB(17); MHex$(Exponent);
PRINT TAB(33); MHex$(Mant1); MHex$(Bytes(1)); MHex$(Bytes(0))
PRINT
LOOP
' MHex$ makes sure we always get two hex digits.
FUNCTION MHex$ (X AS INTEGER) STATIC
D$ = HEX$(X)
IF LEN(D$) < 2 THEN D$ = "0" + D$
MHex$ = D$
END FUNCTION