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pathdel.bat
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DOS Batch File
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1993-11-15
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1KB
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46 lines
@echo off
REM PathDel.bat - remove a directory from the current path, if it's there
if "%1"=="" GOTO SHOW_HOW
if not "%2"=="" GOTO SHOW_HOW
cenvi %0.BAT %1
GOTO FINI
:SHOW_HOW
ECHO PathDel.bat - Delete a directory from the PATH if it's there
ECHO USAGE: PathDel DirSpec
GOTO FINI
GOTO CENVI_EXIT
main(argc,argv)
{
OldDir = argv[1]
if NULL == (Position = FindDirInPath(OldDir))
printf("The Directory \"%s\" is not in PATH.\n",OldDir)
else {
// copy from Path beyond this dir
strcpy(Position,Position+strlen(OldDir))
// if there is a semi-colon at this position, then copy from beyond that too
if (Position[0] == ';')
strcpy(Position,Position+1)
}
}
FindDirInPath(Dir) // search through path for this Dir, return pointer if found
// and return NULL if not found
{
len = strlen(Dir)
p = PATH
do {
if ( 0 == strnicmp(p,Dir,len) && (p[len]==0 || p[len]==';') )
return(p)
p = strchr(p,';')
} while( p++ != NULL )
return(NULL)
}
:CENVI_EXIT
:FINI