home
***
CD-ROM
|
disk
|
FTP
|
other
***
search
/
Freelog 65
/
Freelog065.iso
/
BAS
/
Bureautique
/
Gnumeric
/
gnumeric-1.3.92-rc1.exe
/
analysis-solver.xml
< prev
next >
Wrap
Text File
|
2004-11-01
|
15KB
|
372 lines
<sect1 id="sect-advanced-analysis-solver">
<title>Solver</title>
<para>With Gnumeric Solver you can solve linear programs.</para>
<!-- Add a comment so we keep this picture in figures/. and its
Makefile.am. -->
<!-- solver-05.png -->
<sect2>
<title>Introduction to Linear Programming</title>
<para>A linear program (LP) is a problem that can be expressed as
linear functions. As you probably already know, a linear function
is the one whose graph is always a straight line. Thus each
variable of it appears in a separate term with its coefficient.
There must be no products or quotients of these variables. In
addition, the exponent of each term must be one. No logarithmic,
exponential, trigonometric terms are allowed. Especially note that
functions like ABS, IF, MAX, and MIN are not linear. Here are a
few examples of linear functions:</para>
<programlisting>
3x + y - 5z
-3.23x + 0.33y
-0.3x + 4y - 2z + 1.2m
</programlisting>
<para>The linear problem has a so called objective function which
is to be minimized or maximized and constraints. The objective
function is the one whose value we would like to optimize.
Typically, this function could determine the profit generated by
the expected sales of the given model (maximization problem), or,
the cost of the production in the given environment (minimization
problem). Anyway, on purely mathematical point of view, we could
examine the following objective function:</para>
<programlisting>
Maximize 2x + 3y - z
</programlisting>
<para>In linear programming the variables of this functions are
not allowed to take any values (otherwise the maximum of any
objective function would be infinity). The problem also has
constraints. The constraints are a set of linear functions and a
set of their right hand side values (RHS). For example, for the
previously defined objective function we have the following
constraints:</para>
<programlisting>
x + y <= 5 (#1)
3x - y + z <= 9 (#2)
x + y >= 1 (#3)
x + y + z = 4 (#4)
x, y, z >= 0 (non-negativity assumption)
</programlisting>
<para>This constraint set consists of three inequality constraints
(#1-#3) and one equality constraint (#4). Their RHS values are 5,
9, 1, and 4. In addition, we also have the non-negativity
assumption. That is, all the variables (x, y, and z) have to take
only positive numbers. The idea is to find the optimal values for
the variables (x, y, and z) but also to satisfy all the given
constraints.</para>
</sect2>
<sect2>
<title>Spreadsheet Modeling</title>
<para>To solve optimization problems with Gnumeric you have to
type in the problem into a sheet. A recommended way to start with
is to allocate a separate column in the spreadsheet for each
decision variable (in the previous example the x, y, and z) and a
separate row for each constraint (the constraints #1-#4). The
coefficients of these variables should be placed into the cells
corresponding to the allocated row and the column. It is also
recommended that you label the rows and the columns to make the
sheet much more readable. The sheet for our maximization problem
would look like this:</para>
<figure id="fig-linear-program-example">
<title>Linear programming example</title>
<screenshot>
<mediaobject>
<imageobject>
<imagedata fileref="figures/solver-01.png" format="PNG" />
</imageobject>
<textobject>
<phrase>An image of a worksheet with a linear programing problem.</phrase>
</textobject>
</mediaobject>
</screenshot>
</figure>
<para>As you can see, we have put the model variables into cells
B3:D3. They are currently all zeros. The cell E4 contains the
objective function definition. The easiest way to define it is to
use SUMPRODUCT build-in function. Thus in our model, we have the
formula `=SUMPRODUCT(B3:D3,B4:D4)' in E3.</para>
<para>The constraints are defined in rows seven to ten. Since
the coefficients of these functions are in columns B, C and D we
will get the total sum of each of the constraint using the
formula `SUMPRODUCT(B$3:D$3,Bn:Dn)' where n is the row number of
the constraint. For example, in E7 we have
`=SUMPRODUCT(B$3:D$3,B7:D7)', in E8 `=SUMPRODUCT(B$3:D$3,B8:D8)'
and so on. The right hand side (RHS) values of the constraints
are typed into cells G7:G10.</para>
</sect2>
<sect2>
<title>Using Solver</title>
<sect3>
<title>Solver Parameters</title>
<para>Now it is time to select `Solver...' from the `Tools' menu.
After you have done it, the following dialog will appear:</para>
<figure id="fig-solver-dialog-1">
<title>The empty Solver dialog.</title>
<screenshot>
<mediaobject>
<imageobject>
<imagedata fileref="figures/solver-02.png" format="PNG" />
</imageobject>
<textobject>
<phrase>An image of the solver dialog open to the "Parameters" tab.</phrase>
</textobject>
</mediaobject>
</screenshot>
</figure>
<para>Since we have the objective function in E3 type this into
the `Set Target Cell:' entry. We are about to maximize this
function, thus the radio button `Max' should be pressed on. By
default, the problem is assumed to be maximization problem. The
input variables (x, y, and z) were in cells B3:D3 so type the
cell range into the `By Changing Cells:' entry.</para>
<para>The model to be optimized is a linear model. Thus, we
should check that the check button `Linear (LP/MILP)' is pressed
on under the `Model Assumptions'. Also make sure that the
assume non-negative button is on, otherwise, the input variables
can also take negative values. There is also a check button
`Assume Integer (Discrete)' which adds an integer constraint for
all the input variables. The integer optimization is
described, however, later.</para>
<para>A few additional options can be set too. If you want to
limit the number of iterations the optimization algorithm is
allowed to take you can set the maximum number in the `Max
iterations' entry box. Similarly, you can limit the maximum
time the optimization is allowed to take in the `Max time' entry
box. If either one of these settings is exceeded during the
optimization, the optimization is interrupted and an error
dialog is displayed.</para>
<para>Some models can be better solved if the model is scaled
into another form before the actual optimization. Gnumeric
solver supports automatic scaling which can be checked on by
using the check button on the bottom of the dialog. Note that
the automatic scaling does not change the model since before
checking out the results the model is scaled back to its
original form.</para>
</sect3>
<sect3>
<title>Solver Constraints</title>
<para>Now we can add the constraints. Select the `Constraints'
page from the top of the dialog and the following page should
appear.</para>
<figure id="fig-solver-add-constraint-dialog">
<title>Add constraint dialog.</title>
<screenshot>
<mediaobject>
<imageobject>
<imagedata fileref="figures/solver-03.png" format="PNG" />
</imageobject>
<textobject>
<phrase>An image of the solver dialog open to the "Constraints" tab.</phrase>
</textobject>
</mediaobject>
</screenshot>
</figure>
<para>In this page, you can see all constraints that have been
defined in the `Subject to the Constraints:' window. Since none
has been defined, this window should be empty. Now type in the
constraints (#1-#4) one by one.</para>
<para>When adding constraints, the three entry boxes in the
bottom of the dialog are used. Put a cell name of the total
left hand side (LHS) cell into the `Left Hand Side:' entry box.
In our example, this would be E7 for the constraint #1, E8 for
constraint #2, and so on. The combo entry in the middle defines
the type of the constraint. It can be<![CDATA[ `<=', `=', `>='
]]> , or `Int'. We will explain the `Int' constraints later.
In this example, you should select <![CDATA[ `<=' for
constraints #1-#2, `>=' ]]>for #3, and `=' for constraint #4.
The last entry on the right takes the right hand side values of
the constraints. For constraints #1-#4 they should be G7 (5),
G8 (9), G9 (1), and G10 (4) in this order.</para>
<para>After typing a constraint press
<mousebutton>Add</mousebutton> button, and you will be able to
define the next one. When you have typed in all the
constraints, the Solver dialog should look like this:</para>
<figure id="fig-solver-dialog-2">
<title>The solver dialog</title>
<screenshot>
<mediaobject>
<imageobject>
<imagedata fileref="figures/solver-04.png" format="PNG" />
</imageobject>
<textobject>
<phrase>An image of the solver dialog open to the
"Constraints" tab with constraints entered.</phrase>
</textobject>
</mediaobject>
</screenshot>
</figure>
<para>The order of the constraints does not matter. If you want
to change or delete a constraint click it and then press
`Change' or `Delete' button.</para>
<para>Note that you can also type ranges into the LHS and RHS
entries. For example, you could have typed D7:D8 and G7:G8
instead of the two separate constraints.</para>
<para>If the constraints have now been typed in correctly, we
should check what reports we want to produce.</para>
</sect3>
<sect3>
<title>Solver Reporting</title>
<para>Select the `Reports' page from the top of the dialog and
the a page containing five check buttons should appear. By
pressing these check buttons on, you can produce various kinds of
reports. You can read more about solver reporting in the
following section.</para>
</sect3>
<sect3>
<title>Optimization</title>
<para>After you have specified the parameters, the constraints
and the reporting options it is time to press the `OK' button.
If everything went ok, you will see a dialog saying: `Solver
found an optimal solution. All constraints and optimality
conditions are satisfied.'. This means that the solver found an
optimal solution and the optimal values are now stored into the
input variables. For all models, this, however, does not
happen.</para>
<para>If a feasible solution cannot be found, the solver reports
that `A feasible solution could not be found. All specified
constraints cannot be met simultaneously.'.</para>
<para>If the model is unbounded, the solver reports that `The
Target Cell value specified does not converge! The program is
unbounded.'.</para>
<para>If the maximum number of iterations specified in the
options was exceeded, the solver reports that `The maximum
number of iterations exceeded. The optimal value could not be
found.'.</para>
<para>If the maximum time specified in the options was exceeded,
the solver reports that `The maximum time exceeded. The optimal
value could not be found in given time.'.</para>
</sect3>
</sect2>
<sect2>
<title>Solver Reports</title>
<sect3>
<title>Answer Report</title>
<para>Answer report gives the original and final values for the
problem and for all the input variables and the constraints. In
addition, for the constraints their formulas, binding status and
the slacks are printed out nicely. The answer report is given
as a new sheet.</para>
</sect3>
<sect3>
<title>Sensitivity Report</title>
<para>Sensitivity report gives the shadow prices for the
constraints.</para>
<para>Note that if the model contains integer or boolean
constraints, sensitivity report cannot be produced.</para>
</sect3>
<sect3>
<title>Limits Report</title>
<para>Limits report reports the achieved optimal value all the
input variables of the model with the optimal values and with
upper and lower bound for the optimal value in with the
particular variable could vary without changing the optimal
solution.</para>
<para>If an optimal value for a variable x is 4, for example,
and the lower bound is 2.4 and upper bound 5.9, then x could
take any value between 2.4 and 5.9, and still all the same
constraints were binding as with the optimal value 4. In limits
report, you can also find the value of the target cell for both
upper and lower bound values for the variable. For example, if
the optimal value where x is 4 leads to a profit of $5,000,
limits report specifies that if x is set to 2.4 the profit drops
to $3,640.</para>
<para>Note that if the model contains integer or boolean
constraints, limits report cannot be produced.</para>
</sect3>
<sect3>
<title>Performance Report</title>
<para>Performance reports gives various statistical
characteristics about the given model like how many variables
and rows it contains, and how many non-zero matrix elements it
has. It also gives out the performance numbers like how much
computing time was required to compute the results.</para>
</sect3>
<sect3>
<title>Program Report</title>
<para>Program report gives the model in its mathematical form.
Program report is useful for checking out the correctness of the
model. It can also be useful for educational purposes.</para>
</sect3>
</sect2>
<sect2>
<title>Integer Programming</title>
<para>You can use the Solver tool also for integer programming
(IP) and more generally mixed integer programming. In integer
programming some of the decision variables are required to take on
integer values. To do so, just add a constraint whose type is
`Int'.</para>
</sect2>
</sect1>