home
***
CD-ROM
|
disk
|
FTP
|
other
***
search
/
Geek Gadgets 1
/
ADE-1.bin
/
ade-dist
/
eispack-1.0-src.tgz
/
tar.out
/
contrib
/
eispack
/
ortran.f
< prev
next >
Wrap
Text File
|
1996-09-28
|
3KB
|
87 lines
subroutine ortran(nm,n,low,igh,a,ort,z)
c
integer i,j,n,kl,mm,mp,nm,igh,low,mp1
double precision a(nm,igh),ort(igh),z(nm,n)
double precision g
c
c this subroutine is a translation of the algol procedure ortrans,
c num. math. 16, 181-204(1970) by peters and wilkinson.
c handbook for auto. comp., vol.ii-linear algebra, 372-395(1971).
c
c this subroutine accumulates the orthogonal similarity
c transformations used in the reduction of a real general
c matrix to upper hessenberg form by orthes.
c
c on input
c
c nm must be set to the row dimension of two-dimensional
c array parameters as declared in the calling program
c dimension statement.
c
c n is the order of the matrix.
c
c low and igh are integers determined by the balancing
c subroutine balanc. if balanc has not been used,
c set low=1, igh=n.
c
c a contains information about the orthogonal trans-
c formations used in the reduction by orthes
c in its strict lower triangle.
c
c ort contains further information about the trans-
c formations used in the reduction by orthes.
c only elements low through igh are used.
c
c on output
c
c z contains the transformation matrix produced in the
c reduction by orthes.
c
c ort has been altered.
c
c questions and comments should be directed to burton s. garbow,
c mathematics and computer science div, argonne national laboratory
c
c this version dated august 1983.
c
c ------------------------------------------------------------------
c
c .......... initialize z to identity matrix ..........
do 80 j = 1, n
c
do 60 i = 1, n
60 z(i,j) = 0.0d0
c
z(j,j) = 1.0d0
80 continue
c
kl = igh - low - 1
if (kl .lt. 1) go to 200
c .......... for mp=igh-1 step -1 until low+1 do -- ..........
do 140 mm = 1, kl
mp = igh - mm
if (a(mp,mp-1) .eq. 0.0d0) go to 140
mp1 = mp + 1
c
do 100 i = mp1, igh
100 ort(i) = a(i,mp-1)
c
do 130 j = mp, igh
g = 0.0d0
c
do 110 i = mp, igh
110 g = g + ort(i) * z(i,j)
c .......... divisor below is negative of h formed in orthes.
c double division avoids possible underflow ..........
g = (g / ort(mp)) / a(mp,mp-1)
c
do 120 i = mp, igh
120 z(i,j) = z(i,j) + g * ort(i)
c
130 continue
c
140 continue
c
200 return
end